Question

Need help, please
Question 2: The women of a locality plan to have a Lunch Party as a part of celebration of Women's Day. The women plan to share the cooking work, by each preparing a dish. There were 5 options given for the Main Course. What is the probability that three friends. Ann, Mary and Jane offering to cook three different main course items.
Solution:

P(Ann choosing a different item) = 5/5 =1

P(Mary choosing item different from what Ann has chosen) = 4/5

P(Jane choosing an item different from both Ann's and Mary's choices ) = 3/5

Answer 1

I don't get why P(A) =1

Answer 2

because she is the first to choose, so it has to be different from the others

Answer 3

P(A)=1 because the fraction is 5/5 which would simplify to 1

Answer 4

why not 5C3?

Answer 5

why is 5/5?

Answer 6

forget the 5/5 that is silly

Answer 7

Same with 9/9=1 or why when you have a fraction like 6/5 you would simplify it to 1 1/5 because it is larger than 5

Answer 8

@mantar0078 I know it.
@satellite73 cannot "forget it", because, later on, P (Mary...) =4/5
and P(Jane...) =3/5
those fractions MUST has some meaning

Answer 9

*have

Answer 10

ok sure they mean something

Answer 11

The fractions are the probability

Answer 12

the first person to choose has to choose something that has not been chosen before

Answer 13

so the probability that they choose something un-chosen is one

Answer 14

got that part

Answer 15

oh,i thought that is what you were asking

Answer 16

i quote "I don't get why P(A) =1"

Answer 17

how about 4/5, and 3/5?

Answer 18

ok so one item is chosen yes ?

Answer 19

Yes

Answer 20

that leaves 4 new ones and one old one
pick one of the five at random, the probability you get one of the four unchosen ones is four out of five

Answer 21

Got you. Thank you so much

Answer 22

you're quite welcome