Question

A spring has a natural length of 10 cm. If a 26-N force is required to keep it stretched to a length of 22 cm, how much work W is required to stretch it from 10 cm to 16 cm? (Round your answer to two decimal places.)

Answer 1

Here is my work. But i got the problem wrong :/

Answer 2

work = integral f.dr

Answer 3

first of all did u convert everything to meters

Answer 4

26 = -k((22-10)/100)
k=2600/12
=650/3

Answer 5

hello?`

Answer 6

w=kx^2/2 = 650/3 (0.06)^2/2
=650/6 * 6^2/100^2 = 6.5*6/100 = 0.39 Joules

Answer 7

Yea i did convert. :/

Answer 8

Where did you get -k from?

Answer 9

Oh I get it... Thanks!