Question

What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)?

Answer 1

x2 + y2 − 4x + 2y + 1 = 0

x2 + y2 + 4x − 2y + 1 = 0

x2 + y2 + 4x − 2y + 9 = 0

x2 − y2 + 2x + y + 1 = 0

Answer 2

Those have exponents?

Answer 3

yes lol

Answer 4

sorry the numbers next to x and y are exponents ^2

Answer 5

Ugh I'm still confused

Answer 6

x^2 + y^2 − 4x + 2y + 1 = 0

x^2 + y^2 + 4x − 2y + 1 = 0

x^2 + y^2 + 4x − 2y + 9 = 0

x^2 − y^2 + 2x + y + 1 = 0

Answer 7

the sign ^ means the number after it is an exponent

Answer 8

im pretty sure the answer should be the first two rows

Answer 9

it can only be one

Answer 10

I meant the first 3 row actually because a circle is x^2+y^2=r^2

Answer 11

right

Answer 12

it can only be one of these

Answer 13

A) x2 + y2 − 4x + 2y + 1 = 0

B) x2 + y2 + 4x − 2y + 1 = 0

C) x2 + y2 + 4x − 2y + 9 = 0

D) x2 − y2 + 2x + y + 1 = 0

Answer 14

http://ww2.valdosta.edu/~alazari/math1111/Circle.html

Answer 15

like i said the center is (h,k) so in this case it is (-2,1)

Answer 16

ok so basically you have to separate x and y in groups

Answer 17

but in this case you have to work backward

Answer 18

The distance between these two points is the radius of the circle.

center at (-2, 1) and passing through (-4, 1)?

The points are on the same horizontal line and are 2 units apart.