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OpenStudy (will.h):
set the entire expression equal to zero
try and solve that out for now and tag me when you done that
OpenStudy (sugarmochi):
\[32x^2-38x-24=0 \]
OpenStudy (sugarmochi):
do i start from this? @Will.H
OpenStudy (mathmale):
Starting from "32x^2-40x-12=-8x+12," manipulate the equation so that all terms are on the left side. The right side will automatically be 0 if you'd do that.
Simplify the left side as much as possible. You should get 3 terms. Write them in descending order by powers of x.
Your result?
OpenStudy (sugarmochi):
32x^2-38x-24=0
i think..
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OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
i think so too
OpenStudy (misty1212):
oh actually there is an arithmetic mistake there
OpenStudy (misty1212):
\[-40+8=-32\]
OpenStudy (misty1212):
start with \[32x^2-32x-24=0 \]
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OpenStudy (sugarmochi):
oh sorry bout the mistake !
OpenStudy (misty1212):
then divide by the greatest common factor first
OpenStudy (misty1212):
if that is not clear, divide by 8 , since 8 goes in to each term evenly and get\[4x^2-4x+3=0\] which, by some miracle, factors
OpenStudy (will.h):
or use the famous quadratic formula
\[\frac{ -b \pm \sqrt{b^2 -4ac} }{ 2a }\]