please help solve 32x^2-40x-12=-8x+12
set the entire expression equal to zero try and solve that out for now and tag me when you done that
\[32x^2-38x-24=0 \]
do i start from this? @Will.H
Starting from "32x^2-40x-12=-8x+12," manipulate the equation so that all terms are on the left side. The right side will automatically be 0 if you'd do that. Simplify the left side as much as possible. You should get 3 terms. Write them in descending order by powers of x. Your result?
32x^2-38x-24=0 i think..
HI!!
i think so too
oh actually there is an arithmetic mistake there
\[-40+8=-32\]
start with \[32x^2-32x-24=0 \]
oh sorry bout the mistake !
then divide by the greatest common factor first
if that is not clear, divide by 8 , since 8 goes in to each term evenly and get\[4x^2-4x+3=0\] which, by some miracle, factors
or use the famous quadratic formula \[\frac{ -b \pm \sqrt{b^2 -4ac} }{ 2a }\]
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