Find a and b such that the function is differentiable everywhere x^2-2x+1 if x≤3 f(x)= ax+b if x>3 a=? b=?
Why not make it continuous first, and then calculate the one-sided derivatives?
What I did is I found what f(3) was: 4=a3+b then I found the derivative: 2x-2=ax+b and then i found f'(3) which was 16=a3+b then when I put f(3) and f'(3) together and canceled out I got b=12 but that's the wrong answer @tkhunny
The derivative of ax+b is NOT ax+b.
f(3) = 4 -- That's good. f'(x) = 2x-2 -- That's good. f'(3) = 2(3)-2 = 6-2 = 4 -- Where did you get 16?
Oh I must have still been applying the sq from the original equation instead of just 2(3)-1. So a=4, but where should I plug that in to get B?
Oh nevermind I got it! I was putting in 8 instead of -8. Thank you!!
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