Given the center point and the radius, what is the equation of the circle? Center (-5,12) r=13 1. (x+5)^2 + (y-12)^2=169 2. (x+5)^2 + (y-12)^2=13 3. (x-5)^2 + (y+12)^2 = 169 4. (x-5)^2 + (y-12)^2 = 13
May I help?
Sure!
thanks
Do you know the general form of the circle equation?
Here you are!
(x-h)^2 + (y-k)^2 = r^2 ?
Thanks! how do I plug the numbers into the equation?
x_o is the x-coordinate of the center y_o is the y-coordinate of the center
and raise r to the power 2 when you plug it in the equation, r^2=13^2
Ohh i think I have it, so the answer is 3?
but x_o=-5 not 5 so (x+5)^2 not (x-5)^2
So the numbers get flipped?
if x_o=-ve, then (x+x_o)^2 if x_o=+ve, then (x-x_o)^2 and y the same
Okay, I see so the answer is 1?
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