Given the center point and the radius, what is the equation of the circle?
Center (-5,12) r=13
1. (x+5)^2 + (y-12)^2=169
2. (x+5)^2 + (y-12)^2=13
3. (x-5)^2 + (y+12)^2 = 169
4. (x-5)^2 + (y-12)^2 = 13
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OpenStudy (3mar):
May I help?
OpenStudy (juanilet2000):
Sure!
OpenStudy (3mar):
thanks
OpenStudy (3mar):
Do you know the general form of the circle equation?
OpenStudy (3mar):
Here you are!
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OpenStudy (juanilet2000):
(x-h)^2 + (y-k)^2 = r^2 ?
OpenStudy (juanilet2000):
Thanks! how do I plug the numbers into the equation?
OpenStudy (3mar):
x_o is the x-coordinate of the center
y_o is the y-coordinate of the center
OpenStudy (3mar):
and raise r to the power 2 when you plug it in the equation, r^2=13^2
OpenStudy (juanilet2000):
Ohh i think I have it, so the answer is 3?
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OpenStudy (3mar):
but x_o=-5 not 5
so (x+5)^2 not (x-5)^2
OpenStudy (juanilet2000):
So the numbers get flipped?
OpenStudy (3mar):
if x_o=-ve, then (x+x_o)^2
if x_o=+ve, then (x-x_o)^2
and y the same
OpenStudy (juanilet2000):
Okay, I see so the answer is 1?
OpenStudy (3mar):
Congratulations! ♥
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