I need help with a velocity graph
positive velocity means she was moving upward
remember that velocity is displacement/second so if displacement is 0, it means 0 displacement/second, it was stationary
therefore upward is when positive velocity downward is when negative velocity rest is at zero velocity
can u identify the intervals now?
Let me see...
Well, I thought that from (0,2) and (2,3) it was moving downward, but my teacher's work says that it was (2, 22/5). How does that work?
I mean (0,1) and (2,3)
not 2,3
its not the slope that matters, its all the portion below 0
Oh....
after t=3 the velocity is still negative going to 0, that just means she was slowing down as she was walking backwards
So the particle is at rest from 1≤t≤2 ?
yes
Ok cool, I think I've got it. Thanks for clearing that up for me!
sure, one sneaky thing, u can ask ur teacher about it
at the point t=22/5, it is technically at rest, its an infintessimally small time frame, but i dont know how ur teacher wants to deal with that, its just logistics.
We're only on chapter 2, so I don't think we'll get that specific until some time in the future...
technically its not really an interval, so i think u can ignore that
ok, just wanted to throw that out there
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