Create your own equation written in standard form. Determine any point that is a solution and will be on this line. Justify your answer algebraically. Explain how to find the x- and y- intercept(s) using complete sentences. Write the intercepts as ordered pairs. Rewrite the equation using function notation. Graph the function and show the intercepts.
@Directrix
i thought of an equation and some points but not sure if it satisfies my equation
Do this and then I can help: Create your own equation written in standard form.
y=5x-9
i got some points (-1,4)
The Standard Form for a linear equation in two variables, x and y, is usually given as Ax + By = C where, if at all possible, A, B, and C are integers, and A is non-negative, and, A, B, and C have no common factors other than 1. ----------------------------------- Look in your text and see how standard form of a line is presented in your text.
y=5x-9 Slope/intercept form. It may be considered standard in your book. We want to get off to a good start. So, check to see how your text defines standard form of a line.
actually i got that equation from another open study -_-
liol
its helped on some problems but on this one it's to straight forward
Does your textbook define standard form of the equation of a line?
no it doesn't
Working the problem won't be difficult. If only I could get you to tell me how your book defines standard form of a linear equation.
it doesn't so just tell me how you define it
my teacher talked about Ax+Bx=C
The standard form of an equation is Ax + By = C. In this kind of equation, x and y are variables and A, B, and C are integers. Okay, let's go with what the teacher said. First, we will need to write y = 5x -9 in standard form.
okay how do we do it
y = 5x - 9 -y -y ---------- 0 = 5x - y - 9 +9 +9 ------------- 9 = 5x - y 5x -y = 9 ---> standard form (do you agree)
yes very
If you agree, then this solution begins with the equation: 5x -y = 9 What is the first step now that we have the equation in standard form?
+y
Determine any point that is a solution and will be on this line. Justify your answer algebraically. Where are the coordinates of the point you posted are on this line?
wait no!
-5x from both sides
how do i get the right coordinates or they can be random?
You posted this point earlier in the thread: >> i got some points (-1,4)
yes but that was random
Let's see if the point is on the line. Is (-1,4) on the line? 5x -y = 9 x = -1 and y = 4 Does 5* (-1) - 4 = 9 ? yes or no
it equals -9=9 so no?
5* (-1) - 4 = -5 -4 = -9 which is not on the line We need another point.
In the equation if x = 0, what is the value of y that goes with that?
5x -y = 9 5*0 - y = 9 ---> Solve for y
how about 2,2?
(2,2) is not on the line. Please do this: 5*0 - y = 9 ---> Solve for y
-y=9
so -9?
Yes. ( 0. -9) is a point on the graph of 5x -y = 9 because 5*0 - (-9) = 9
Explain how to find the x- and y- intercept(s) using complete sentences. Write the intercepts as ordered pairs. The x-intercept is on the x-axis. All points on the x-axis have a y-coordinate of 0. To find the x-intercept, let y = 0 in the equation 5x -y = 9. 5*x - 0 = 9 5x = 9 x = 9/5 = 1.8 ( 1.8 , 0 ) for the x-intercept.
okay but how come your way is different from hers? https://prezi.com/2kuanyteuuw_/304-module-3-quiz/
The video will not load. If you want to work with "her," then I will leave you to do that.
@563blackghost
this is alot i cant comprehend and also its the week end no ones on here much
@sammixboo
@Jamierox4ev3r
@Austin.L
you know how to do this?
@mathmate
@sweetburger
@CaNdI5a18
hey austin
nevermind
Join our real-time social learning platform and learn together with your friends!