Question

Find all of the zeros and write a linear factorization of the function.
f(x)=x^4+x^3+4x^2-4x-32

Answer 1

May I help?

Answer 2

Yes

Answer 3

this?\[f(x)=x ^{4}+x ^{3}+4x ^{2}-4x-32\]

Answer 4

f(x)=x^4+x^3+4x^2-4x-32

Answer 5

@TGstudios
it is your turn.

Answer 6

XD... this is calulus1LOL... I have no clue what calculus is!!

Answer 7

No need to calculus!
It is just factorizing by grouping, no more!

Answer 8

This is Pre-Calculus Work!

Answer 9

Can you proceed?

Answer 10

\[factors~ of ~32 ~are~ \pm1,\pm2,\pm4,\pm8,\pm 16 \]
try x=2,
\[f(2)=2^4+2^3+4*2^2-4*2-32=16+8+16-8-32=0\]
so x=0 is a zero of f(x)