Question

A bullet is fired from a gun at an acceleration of 425 m/s2. If the force on the bullet when it is fired is 1.1 N, what is the mass of the bullet?

2.6 x 10^-3 kg

3.86 x 10^2 kg

4.7 x 10^2 kg

4.2 x 10^-3 kg
@mathmale

Answer 1

Use the formula:

Force(N) = mass(kg) * acceleration(m/s^2)

So if you plug the numbers in:
1.1(N) = mass(kg) * 425(m/s^2)

Answer 2

ok so would i divide 1.1/ 425?

Answer 3

@mhchen

Answer 4

Ye

Answer 5

i got .00258824

Answer 6

@mhchen

Answer 7

Yeah same here, so then you'd convert that to scientific notation and yea.

Answer 8

i got a @mhchen

Answer 9

Yeah, same here. You said you needed help converting into scientific notation?

Answer 10

0.00258824 is about 0.0026 rounded.
So scientific notation always starts like
2.6 * 10^something
and we count the number of places the '2' moved to the right:
2.6 <-- initial place
0.26 <-- first place
0.026 <-- second place
0.0026 <-- third place

Since it moved by 3 times to the RIGHT, it's 10^-3
2.6 * 10^-3

Answer 11

thank you can you help with a couple more?

Answer 12

nope sorry, i g2g.