someone please help will medal and fan
\[f(x)=\frac{ x+4 }{ 2x-5 }\]
find the inverse
prepared for some algebra ? (a lot of algebra!)?
oh no. sure.
i would start by putting \[y=\frac{ x+4 }{ 2x-5 }\], then switch x and y (because that is what the inverse does) and write \[x=\frac{ y+4 }{ 2y-5 }\] then solve for \(y\)
any idea how to do that?
nope. no clue
ok then how about this easier problem \[\frac{y+4}{2y-5}=10\] can you solve that? what is a first step?
would you multiply both sides by 2y-5?
yes
so that would be the first step to solving the one where its equal to x?
yes, but lets do this one first, so it makes sense
ok so after you multiply both sides by 2y-5, you would get 20y-50=y+4, then you would subtract y from both sides, add 50 to both sides, and get 54/19
ok so first step is to multiply by \(2y-5\) next step was to distribute go ahead and do it with the x instead of the 10
i got\[2xy-5x=y+4\]
yup now with 10 instead of x you subtracted y from both sides, you need to do that here
how would you subtract y from the side with 2xy-5x?
just write it is all
oh alright so 2xy-y-5x=4?
yes now with the 20 you added 50 to both sides, with \(-5x\) you have to add \(5x\) to both sides (just write it )
2xy-y=5x+4
right now here is the part that is slightly different than with the numbers
you had \(20y-y=19y\) but here you have \(xy-y\) on the left what you do is factor the \(y\) out of the expression on the left hand side
ohh ok so then after you do that, you get y(2x-1)=5x+4, and then you just divide both sides by 2x-1. so then the inverse is y=(5x+4)/(2x-1)?
oops sorry you have \[2xy-y\] but same idea
yes you got it
thank you so so much!!
or rather \[f^{-1}(x)=\frac{5x+4}{2x-1}\] you are welcome
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