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Mathematics 13 Online
OpenStudy (owlstudies):

someone please help will medal and fan

OpenStudy (owlstudies):

\[f(x)=\frac{ x+4 }{ 2x-5 }\]

OpenStudy (owlstudies):

find the inverse

satellite73 (satellite73):

prepared for some algebra ? (a lot of algebra!)?

OpenStudy (owlstudies):

oh no. sure.

satellite73 (satellite73):

i would start by putting \[y=\frac{ x+4 }{ 2x-5 }\], then switch x and y (because that is what the inverse does) and write \[x=\frac{ y+4 }{ 2y-5 }\] then solve for \(y\)

satellite73 (satellite73):

any idea how to do that?

OpenStudy (owlstudies):

nope. no clue

satellite73 (satellite73):

ok then how about this easier problem \[\frac{y+4}{2y-5}=10\] can you solve that? what is a first step?

OpenStudy (owlstudies):

would you multiply both sides by 2y-5?

satellite73 (satellite73):

yes

OpenStudy (owlstudies):

so that would be the first step to solving the one where its equal to x?

satellite73 (satellite73):

yes, but lets do this one first, so it makes sense

OpenStudy (owlstudies):

ok so after you multiply both sides by 2y-5, you would get 20y-50=y+4, then you would subtract y from both sides, add 50 to both sides, and get 54/19

satellite73 (satellite73):

ok so first step is to multiply by \(2y-5\) next step was to distribute go ahead and do it with the x instead of the 10

OpenStudy (owlstudies):

i got\[2xy-5x=y+4\]

satellite73 (satellite73):

yup now with 10 instead of x you subtracted y from both sides, you need to do that here

OpenStudy (owlstudies):

how would you subtract y from the side with 2xy-5x?

satellite73 (satellite73):

just write it is all

OpenStudy (owlstudies):

oh alright so 2xy-y-5x=4?

satellite73 (satellite73):

yes now with the 20 you added 50 to both sides, with \(-5x\) you have to add \(5x\) to both sides (just write it )

OpenStudy (owlstudies):

2xy-y=5x+4

satellite73 (satellite73):

right now here is the part that is slightly different than with the numbers

satellite73 (satellite73):

you had \(20y-y=19y\) but here you have \(xy-y\) on the left what you do is factor the \(y\) out of the expression on the left hand side

OpenStudy (owlstudies):

ohh ok so then after you do that, you get y(2x-1)=5x+4, and then you just divide both sides by 2x-1. so then the inverse is y=(5x+4)/(2x-1)?

satellite73 (satellite73):

oops sorry you have \[2xy-y\] but same idea

satellite73 (satellite73):

yes you got it

OpenStudy (owlstudies):

thank you so so much!!

satellite73 (satellite73):

or rather \[f^{-1}(x)=\frac{5x+4}{2x-1}\] you are welcome

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