Write the point-slope form of the line that passes through (1, -5) and is perpendicular to a line with a slope of 1.
is there a graph?
No, they just gave me that equation and they want me to write out how I worked it. I'm totally stuck
oh hmmm wait ill try not sure if ican do its maybe @jabez177 @pooja195 or @Austin.L
Ok, thanks!
Point slope form Do you remember the form?
y - y1 = m(x - x1)
i would say (-1, 5) jab should know if im right
Ohhhh!! This form? Eeks... This is my least favorite one... Practice makes perfect. :)
XD
Ugh, I hate it so much! >_< My teacher isn't really that big of a help either. I'm like, "Dude, I'm going for broadcast journalism. I don't need this stupid point slope form crap"
Alright so first off. We have to plug in the numbers
\(\color{#0cbb34}{\text{Originally Posted by}}\) @tparker22 y - y1 = m(x - x1) \(\color{#0cbb34}{\text{End of Quote}}\) You have this info down just plug in your given numbers
m=slope
y – y1 = m(x – x1) So we just put in 5 where the Y1 is and the -1 where the x1 is
You get the picture?
Ok, so would that be y - y6 = m(x - x-1)
Take out the y you are replacing it same with x
m is the slope What is the slope in the question?
The question says -3
\(\color{#0cbb34}{\text{Originally Posted by}}\) @tparker22 Write the point-slope form of the line that passes through (1, -5) and is perpendicular to a line with a slope of 1. \(\color{#0cbb34}{\text{End of Quote}}\) It says "slope of 1" m=slope
Oops, I'm sorry! I was looking at the wrong question. I clicked on the wrong one, okay I'm back to the one we're all currently on
So it would really be y - y5 = m(x - x1) ?
I mean, I can plug in the info, but I can't work it. That's my issue If one of y'all could explain in detail step by step, that'd be perfect and maybe I could take it from there with the rest of my problems
pooja you stole my qustion! oh well i need to go bye
Basically we have a point slope formula \[\huge y-y_1=m(x-x_1)\] where m=slope (x1,y1) In this particular problem you are given that: x=1 y=-5 slope which is m=1 You take this information and you plug it in place of the variables present in the formula
Okay, I get that so far
Can you tell me, what equation we would have once we plug in our numbers? Keeping in mind that when two minus signs are next to each other it becomes a +
We would have ----- y - y5 = 1(x-x1) ?
or would every y be 5 and every x be 1?
You are correct thus with a minor mistake y +5 = 1(x-x1)
Continue with plugging in your x value
Ok so since we have this - y + 5 = 1(x-x1) - then we would continue with plugging in the x value you said. My current x value is 1, so would be be y + 5 = 1(1-x1)? see, this is where I get confused, I'm sorry :/
You need to plug your x value in the x1 spot
That would be 1 * 1 then, which is 1?
No x1 is part of the coordinate (1,-5) x1=1
Ok
plug it in
Okay, so I plugged these numbers in and did a bit more. Would this be it?
(y-y1)=m(x-x1) (y--5)=1(x-1) y=1x-1+-5 y=1x-6 1x-y-6=0
(y--5)=1(x-1) Correct but \[\huge~\rm~\bf~ y+5=1(x-1)\] \[\huge~\rm~\bf~ y+5=1x-1\] \[\huge~\rm~\bf~ y=1x-6\] \[Perpendicular~slope=Flipped~sign+Reciprocal~(flipped fraction) \]
Ok! :)
Whats the opposite of 1?
-1
So parallel is positive, perpendicular is opposite?
-negative I meant
Not really I suggest you use this site to help you differentiate between the 2 https://www.mathsisfun.com/algebra/line-parallel-perpendicular.html
Or is it the other way around?
Okay, I'll look into it! Thank you!
Parallel--->slopes stay the same Perpendicular---->Flip the fraction and if there isn't one make one by adding a 1 to the bottom, and flip the sign (positive # goes to negative; negative # goes to positive)
okay! thank you :)
You're welcome.
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