Help please!!!

Question

Help please!!!

zarkam21 · Answer

attachment

mathmate · Answer

@zarkam21 Didn't you tag me from the identical post? http://openstudy.com/study#/updates/580e4765e4b075d6916ed681

campbell_st · Answer

well a general vertex form of the parabola is 

$$(x - h)^2 = 4a(y - k)$$

where the vertex is at (h, k) and the focal length is a. 

I can rewrite this to another vertex form of 

$$y = \frac{1}{4a} (x - h)^2 + k$$

so you know h = 3 and k = 2

so the equation is 

$$y = \frac{1}{4a} (x - 3)^2 + 2$$

you now use the point (4, 6) and substitute it into the equation above to find a. 

when you get that you'll have the equation of the parabola.

zarkam21 · Answer

@mathmate  yes I ended up reposting the question

zarkam21 · Answer

So the answer would be which one of the choices?

campbell_st · Answer

it usually is... unless there is a typo

zarkam21 · Answer

What do you mean it usually is

mathmate · Answer

@zarkam21
Finding which of the choices is your job!
If you need further help to find the solution, you're welcome to ask.