Question

Helplease

Answer 1

There are several equations for a parabola; all are quadratic equations.
One is y=ax^2+bx+c; another is \[y-k=a(x-h)^2...\] where (h,k) is the vertex.

Which equation would serve you better here? Why?

Start substituting known values into that equation.

Answer 2

So y-3=a(x-2)^2 ?

Answer 3

But the vertex is at (3,2): h=3 and k=2. Mind fixing your result? y-3=a(x-2)^2 ?

Answer 4

y-2=a(x-3)^2

Answer 5

@agent0smith is this correct?

Answer 6

Yes, then plug in the other point given on the graph, to solve for a.

Answer 7

What is the other point, I plugged in the vertex

Answer 8

It's given on the graph...

Answer 9

6-2=a(4-3)^2

Answer 10

Now you can find a.

Answer 11

4

Answer 12

So the answer choice B?

Answer 13

Hello?

Answer 14

Looks about right

y-2=a(x-3)^2

plug in your value of a and simplify.

Answer 15

Well I got 4

Answer 16

that a=4

Answer 17

y-2=a(x-3)^2
(add 2)
y=a(x-3)^2 + 2

Answer 18

Which one has (x-3) and + 2?

Answer 19

Only one has this answer, so it is definitely your answer.

Answer 20

B

Answer 21

Correct, good job!