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OpenStudy (imterribleatmath):
@agent0smith
OpenStudy (agent0smith):
Plug in x=-1.
OpenStudy (imterribleatmath):
what do u mean plug in?
OpenStudy (kittiwitti1):
Plug in means to replace the variable \(x\) with the value stated for it.
Example: if you have an equation \(y=3x+5\), and \(x=6\), then plugging in will get you this:\[y=3(\color{red}{6})+5\]
OpenStudy (kittiwitti1):
He is asking you to replace \(x\) with the value \(-1\).
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OpenStudy (imterribleatmath):
ok got that
OpenStudy (kittiwitti1):
Now you have a complete equation that you can solve for, yes?
Can you try and do that?
OpenStudy (kittiwitti1):
Are you confused? @imterribleatmath
OpenStudy (imterribleatmath):
yes
OpenStudy (kittiwitti1):
Alright. Where are you confused?
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OpenStudy (imterribleatmath):
what is my full equation?
OpenStudy (imterribleatmath):
to solve
OpenStudy (kittiwitti1):
You have equation model \(\Large{-5^{\color{red}{x}}}\). You are also given the value for x, which is \(\color{red}{x=-1}\).
OpenStudy (kittiwitti1):
Replace \(x\) with \(-1\) and you get \(\Large{-5^{\color{red}{-1}}}\)
OpenStudy (imterribleatmath):
oh ok
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OpenStudy (kittiwitti1):
Yes.
Are you good now? I can explain more if you need. :-)
OpenStudy (imterribleatmath):
so my equation to solve is y=f(x)=-5^-1 ?
OpenStudy (kittiwitti1):
Yes.
OpenStudy (kittiwitti1):
I will give you a hint.
Given variable \(a\), if you have function \(G(x)=a^{-c}\) then you can also put it in the form \(\Large{\frac{a}{a^{c}}}\).
OpenStudy (kittiwitti1):
In this problem the \(a^{-c}\) is the function \(f(x)\) which is \(-5^{-1}\). Apply the rule to the equation and solve.
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OpenStudy (kittiwitti1):
In words: If you have \(a\) to the negative power of \(c\), then you will be able to write it in the fraction form:\[\frac{1}{a^{c}}\]Otherwise known as "one over \(a\) to the power of \(c\)"
OpenStudy (imterribleatmath):
i understand my equation but whats f(x) equal?
OpenStudy (kittiwitti1):
You have the result from substituting the \(x\) value in. You now have \(\large{f(-1)=-5^{-1}}\) which can be simplified FURTHER.
Based on the hint I gave you, any ideas?
OpenStudy (imterribleatmath):
f(-1)= -1/5 ?
OpenStudy (kittiwitti1):
Yes! Very good job. \(\large{☺}\)
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OpenStudy (imterribleatmath):
so now i have -1/5 what now ?
OpenStudy (kittiwitti1):
I believe you are done. Did you try to put it into the system and see if you are correct?
OpenStudy (imterribleatmath):
it says express as a decimal round to the nearest thousand ?
OpenStudy (kittiwitti1):
Okay then, do you know how to turn a fraction into a decimal?
OpenStudy (imterribleatmath):
0.2?
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OpenStudy (kittiwitti1):
Yes, but they want it "to the nearest thousand."
Hint: \(0.0358000=0.0358\)
OpenStudy (imterribleatmath):
im not sure how to do that
OpenStudy (kittiwitti1):
Refer to my hint.
Another hint: \(0.56=0.560\), but the \(\color{blue}{\text{second}}\) number is the one that has a thousandth place.
OpenStudy (imterribleatmath):
is it 0.200
OpenStudy (imterribleatmath):
thats my anwser?
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OpenStudy (kittiwitti1):
Did you try to put it in to see if it is correct?
OpenStudy (imterribleatmath):
yes was incorrect maybe i did something wrong ?
OpenStudy (kittiwitti1):
You are missing something.\[-\frac{1}{5}\ne0.200\]
OpenStudy (agent0smith):
LOL you missed the negative.
OpenStudy (imterribleatmath):
im confused?
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OpenStudy (kittiwitti1):
\(\Large{-\frac{1}{5}}=\) what in decimal form?
OpenStudy (imterribleatmath):
was it, -0.200 because i missed the negative?
OpenStudy (kittiwitti1):
Yes lol
OpenStudy (imterribleatmath):
my bad
OpenStudy (kittiwitti1):
That's okay. Did it say the answer is correct now?
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OpenStudy (imterribleatmath):
i only get one chance to anwser
OpenStudy (kittiwitti1):
Wow, that's not a very friendly site then.
Does it at least tell you what the right answer was supposed to be?
OpenStudy (imterribleatmath):
nope
OpenStudy (agent0smith):
You only got one chance?
OpenStudy (kittiwitti1):
Welp, sorry. Better luck next time then :p
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