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Mathematics 17 Online
OpenStudy (a1234):

You are trying to push a 90-kg sofa 4 meters to the other side of the hall. You use a steady horizontal force of 600 N. The coefficient of kinetic friction between the sofa and floor is 0.6. Find the magnitude/direction of the total force on the sofa, magnitude/direction of the acceleration of the sofa's acceleration, and how long it would take to push the sofa four feet.

OpenStudy (a1234):

I found the frictional force to be 530 Newtons. How do I do the rest? Below is an illustration of the given diagram.

OpenStudy (a1234):

@mathmale

OpenStudy (akshvas):

You've figured out the right direction of the frictional force too right?

OpenStudy (akshvas):

The acceleration would be (F-(mu*m*g)) /m in the direction of the external force (600N)

OpenStudy (akshvas):

Initially the sofa was at rest so initial velocity is zero, Displacement to be covered is 4 feet And acceleration is now known too Use the second question of motion to find the time taken

OpenStudy (a1234):

But what is the total force?

OpenStudy (akshvas):

600N - the frictional force This is the force which drives the sofa forward

OpenStudy (akshvas):

I meant 600 N minus the frictional force

OpenStudy (518nad):

its 90 pounds not kg

OpenStudy (akshvas):

Yes, do the appropriate conversions to get the accurate answer

OpenStudy (a1234):

Pounds...sorry But the frictional force is 530 N

OpenStudy (518nad):

that sounds too big, i think theres some mistake in conversion

OpenStudy (518nad):

how many kg is 90lb

OpenStudy (a1234):

No need for conversion...it's only in pounds

OpenStudy (518nad):

oh my gudness

OpenStudy (a1234):

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