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Mathematics 21 Online
OpenStudy (devonhoward15):

@563blackghost

563blackghost (563blackghost):

Yes?

OpenStudy (devonhoward15):

OpenStudy (devonhoward15):

i need the coordinates

563blackghost (563blackghost):

We can solve this by using the distance. The distance from `(-2,2) to (-8,2)` is 6 units. We would divide that by 3 to find the changed distance between the two points. You would apply the same thing to `(-2,2) to (-2,8)` since it also has a distance of 6 units.

OpenStudy (devonhoward15):

so those are the first two coordinates?

OpenStudy (devonhoward15):

(-2,2) (-2,8)

563blackghost (563blackghost):

So 6/3 is 2 so the distance between the points can only be 2. So we would subtract 4 units from x. \(\huge\bf{(-8-4,2)}\) \(\huge\bf{(-2,8-4)}\)

563blackghost (563blackghost):

\(\huge\bf{(-8+4,2)}\)*

OpenStudy (devonhoward15):

sorry if im not catching you... i just kicked out of my house

OpenStudy (devonhoward15):

which are the coordinates i need to plot?

563blackghost (563blackghost):

You need to solve it. Since we go down to a distance of 2 units we apply 4 units to the x-value. `(-8+4,2)` `(-2,8-4)`

OpenStudy (devonhoward15):

so that would be (-4,2) and (-2,4) correct?

OpenStudy (devonhoward15):

@563blackghost

563blackghost (563blackghost):

Correct :)

OpenStudy (devonhoward15):

and how do we get the 3rd coordinate? is it (-2,2)

OpenStudy (devonhoward15):

thanks

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