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563blackghost (563blackghost):
Yes?
OpenStudy (devonhoward15):
OpenStudy (devonhoward15):
i need the coordinates
563blackghost (563blackghost):
We can solve this by using the distance. The distance from `(-2,2) to (-8,2)` is 6 units. We would divide that by 3 to find the changed distance between the two points. You would apply the same thing to `(-2,2) to (-2,8)` since it also has a distance of 6 units.
OpenStudy (devonhoward15):
so those are the first two coordinates?
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OpenStudy (devonhoward15):
(-2,2) (-2,8)
563blackghost (563blackghost):
So 6/3 is 2 so the distance between the points can only be 2. So we would subtract 4 units from x.
\(\huge\bf{(-8-4,2)}\)
\(\huge\bf{(-2,8-4)}\)
563blackghost (563blackghost):
\(\huge\bf{(-8+4,2)}\)*
OpenStudy (devonhoward15):
sorry if im not catching you... i just kicked out of my house
OpenStudy (devonhoward15):
which are the coordinates i need to plot?
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563blackghost (563blackghost):
You need to solve it. Since we go down to a distance of 2 units we apply 4 units to the x-value.
`(-8+4,2)`
`(-2,8-4)`
OpenStudy (devonhoward15):
so that would be (-4,2) and (-2,4) correct?
OpenStudy (devonhoward15):
@563blackghost
563blackghost (563blackghost):
Correct :)
OpenStudy (devonhoward15):
and how do we get the 3rd coordinate? is it (-2,2)
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