Question

so an object is dropped from 1.6 m(eters) above the ground.

its initial velocity is 5 m/s, and it accelerates at -9.8 m/s.

how long would it take for the object to fall 1.6 m and hit the ground?

Answer 1

0.26 sec

Answer 2

answer my question pls
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Answer 3

There is probably an easier way of doing this however this is how I (hopefully) solved it.

I am going to use two kinematics formulas.

Firstly \[v ^{2}=u ^{2}+2as\]
and secondly v=u +at.

Where v is the final velocity, u is the initial velocity, s is the displacement, t is time, and a is the acceleration of freefall.

Start by using the first formula to find the final velocity (this might seem irrelevant)

you should get a value of v =7.51

Then use the second formula

v=u +at

rearrange to get \[t=\frac{ v-u}{ a}\]

substitute and you should get t = 0.25580639... seconds.

Hopefully that is the correct time taken to hit the ground.

Answer 4

Nice