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Mathematics 8 Online
OpenStudy (campayne):

Use Cramer's rule to solve the system of equations.

OpenStudy (campayne):

OpenStudy (vuriffy):

Are you familiar with Cramer's rule?

OpenStudy (vuriffy):

It is a method to find the value of X and Y, and also Z in other cases.

OpenStudy (campayne):

ive not in the slighest clue every time i try i feel like i get it less and less

OpenStudy (vuriffy):

You were not taught this concept yet?

OpenStudy (campayne):

fraid not

OpenStudy (vuriffy):

http://www.purplemath.com/modules/cramers.htm Look at this, hopefully you may see some correlations, but I will help you through it.

OpenStudy (wolf1728):

Or you can check this web page: http://www.1728.org/cramer.htm

OpenStudy (vuriffy):

@CamPayne That one is more detailed in the steps required, the one I commented does not fully show every step.

OpenStudy (campayne):

okay can you guys just walk me through this one a small step at a time

OpenStudy (wolf1728):

Want me to do it vurify?

OpenStudy (vuriffy):

First off, I believe you must get the x and y value on one side and the numerical value on the other.

OpenStudy (campayne):

so how does you do that

OpenStudy (vuriffy):

@wolf1728 If you wish, but I have knowledge of this, also I do not mind if you want to. If I do, please correct me if I make any mistakes.

OpenStudy (vuriffy):

See, you have: 6x = 2 - y 3x+1 = 2y

OpenStudy (vuriffy):

What would you do to move the y to the other side? For: 6x = 2 - y ?

OpenStudy (campayne):

umm i suppose you'd add y or something?

OpenStudy (vuriffy):

Correct. Which would result into: 6x + y = 2. Now, let's look at: 3x + 1 = 2y Two steps for this one.

OpenStudy (campayne):

kay

OpenStudy (wolf1728):

Step 1 3x + 1 = 2y Add -1 to both sides

OpenStudy (wolf1728):

3x -1 +1 = 2y -1 What does that become?

OpenStudy (campayne):

um 3x + y?

OpenStudy (campayne):

i think thats wrong

OpenStudy (wolf1728):

It is wrong - try again.

OpenStudy (vuriffy):

(-1+1) = ?

OpenStudy (campayne):

0

OpenStudy (vuriffy):

Which would result to: 3x = 2y - 1. Now, we have to move the y to the other side, what would you do?

OpenStudy (vuriffy):

Also, the 2 and y will stay together.

OpenStudy (wolf1728):

Basically, you are moving 2y to the other side

OpenStudy (campayne):

okay

OpenStudy (vuriffy):

Just like the one incident: What would make (2y (+/-) (value)) = 0. To cancel it out from that side and move it to the other? Would you add it, or subtract it?

OpenStudy (campayne):

looks like subtract

OpenStudy (vuriffy):

Correct, which would result to: 3x - 2y = -1 Now, your two equations are: 6x + y = 2. 3x - 2y = -1.

OpenStudy (vuriffy):

Now, you have to find out what is: a, b, c, d, e, and f.

OpenStudy (vuriffy):

You first count the coefficient of the x and y values then the numerical values they are equal to.

OpenStudy (vuriffy):

So, hint, a = 6, what do you think b is ?

OpenStudy (campayne):

a? i only see Xs and Ys

OpenStudy (wolf1728):

To use Cramer's Rule you have to think of the first equation as: ax + by = e

OpenStudy (vuriffy):

This is in relevance to Cramer's Rule.

OpenStudy (campayne):

i see

OpenStudy (vuriffy):

So, what do you think b is now?

OpenStudy (vuriffy):

This will eventually help us find the determinant's numerator, which then helps us find the values of x and y.

OpenStudy (campayne):

-1 is b -1?

OpenStudy (vuriffy):

ax + by = e. 6x + y = 2. 3x - 2y = -1.

OpenStudy (vuriffy):

Try now.

OpenStudy (campayne):

so am i solving really for x?

OpenStudy (vuriffy):

You will solve for x and y, eventually, you have other steps to do beforehand.

OpenStudy (vuriffy):

We must find out the values for a, b, c, d, e, f. There is this many variables, because there is this many values displayed.

OpenStudy (vuriffy):

How many y's is y?

OpenStudy (campayne):

1?

OpenStudy (vuriffy):

Yes. b = 1.

OpenStudy (campayne):

yay

OpenStudy (vuriffy):

ax + by = e. 6x + y = 2. 3x - 2y = -1. a = 6, b =1, c = ?, d = ? Now look at only (3x - 2y).

OpenStudy (vuriffy):

Can you tell me what c and d = from that?

OpenStudy (wolf1728):

That should be cx + dy = f

OpenStudy (vuriffy):

I just realized that, also, thank you.

OpenStudy (vuriffy):

cx + dy = f. 3x - 2y = -1.

OpenStudy (campayne):

okay soo then what? i solve for c?

OpenStudy (vuriffy):

Just find what c and d equal from what the equation states, just like a and b. Hint c is the coefficient of x, and d is the coefficient of y.

OpenStudy (vuriffy):

C = 3. D = -2. Do you understand that?

OpenStudy (campayne):

not quite how is that??????

OpenStudy (vuriffy):

cx + dy = f. 3x - 2y = -1. Coefficient means the value in front of a variable. The value in front of x is 3. The value in front of y is -2. (Subtraction sign makes it negative.)

OpenStudy (campayne):

okay but which ones are d and y?

OpenStudy (vuriffy):

C = 3. Which was the coefficient, in front of x. D = -2. Which was the coefficient, in front of y.

OpenStudy (campayne):

ohhh i see now

OpenStudy (vuriffy):

So, a = 6, b = 1, c = 3, d = -2, e = ?, f = ? The numerical values they are equal to, so then e = 2. f = -1. Do you understand this part?

OpenStudy (campayne):

yeah i do now

OpenStudy (campayne):

im sorry if i seem like a lost cause

OpenStudy (vuriffy):

dn = (a • d) - (c • b)

OpenStudy (vuriffy):

What I would you about earlier, plug in those values then you will find it, this helps you solve for x and y.

OpenStudy (vuriffy):

dn = (6 • -2) - (3 • 1) = ?

OpenStudy (campayne):

so -12 minus 3

OpenStudy (vuriffy):

Yes, = -15.

OpenStudy (campayne):

kay so what do we do with that

OpenStudy (vuriffy):

x = [(e • d) - (f • b)] ÷ dn

OpenStudy (vuriffy):

a = 6, b = 1, c = 3, d = -2, e = 2, f = -1

OpenStudy (vuriffy):

x = [(2 • -2) - (-1 • 1)] ÷ -15

OpenStudy (vuriffy):

x = ?

OpenStudy (vuriffy):

Hint: double negative makes positive.

OpenStudy (campayne):

so 15

OpenStudy (vuriffy):

[(-4)-(-1)] / -15 = ?

OpenStudy (vuriffy):

Brackets mean you perform first.

OpenStudy (campayne):

-5

OpenStudy (vuriffy):

-4 + 1 / -15 = ?

OpenStudy (campayne):

5

OpenStudy (vuriffy):

With brackets around -4 + 1. NEGATIVE 4 PLUS POSITIVE ONE = NEGATIVE 3.

OpenStudy (vuriffy):

-3 / -15. Is not the same as -15/-3.

OpenStudy (campayne):

0.2?

OpenStudy (vuriffy):

CORRECT.

OpenStudy (vuriffy):

X = 0.2 One done, now y.

OpenStudy (wolf1728):

Very good !!

OpenStudy (campayne):

oh boy

OpenStudy (vuriffy):

a = 6, b = 1, c = 3, d = -2, e = 2, f = -1 y = [(a • f) -(c • e)] ÷ dn

OpenStudy (vuriffy):

a = 6, b = 1, c = 3, d = -2, e = 2, f = -1 y = [(6 • -1) -(3 • 2)] ÷ -15.

OpenStudy (vuriffy):

Remember do the actions in the brackets first before dividing by -15.

OpenStudy (campayne):

0.8?

OpenStudy (vuriffy):

Yes, wonderful. X = 0.2 Y = 0.8

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