Question

find Fog (x)

Answer 1

could someone explain how to do this please?

Answer 2

Is this f(x)?\[f(x)=\frac{ 1 }{ x }+1\]

Answer 3

\[1 /x+1\]

Answer 4

x+1 is the denominator

Answer 5

ok got ya. next time put the denominator in parentheses to avoid confusion :)

Answer 6

okay sorry Lol

Answer 7

to solve this, you have to replace the x in f(x) with the expression from g(x).\[f(x)=\frac{ 1 }{ x+1 }\]
replace the \(x\) with \(-\frac{1}{x}\).
\[f~o~g(x)=f(g(x))=\frac{ 1 }{ - \frac{ 1 }{ x }+1}\]
Do you know how to simplify that?

Answer 8

Yeah I got to there I just dont know how to simplify :( the fraction within a fraction confuses me

Answer 9

you have to multiply both numerator and denominator by the common denominator. In this case, \(x\) is the only denominator
\[f~o~g(x)=\frac{ 1(x) }{x\left( - \frac{ 1 }{ x }+1 \right)}{}\]

Answer 10

??

Answer 11

yes