Question

Write the matrix equation for the system, and then solve.

Answer 1

writing it out is easy
Ax=B
where
\[A= \left[\begin{matrix}3 & -2 \\ 2 & -3\end{matrix}\right]\]
\[X=\left(\begin{matrix}x \\ y\end{matrix}\right)\]
\[B=\left(\begin{matrix}4 \\ 11\end{matrix}\right)\]

Answer 2

calculating, either involves finding a nice calculator, or using the inverse property of a matrix

Answer 3

\[A^{-1} A = A A^{-1}=I\]
where I is the identity matrix

Answer 4

if we multiply the inverse matrix to both sides \[A^{-1}A X=A^{-1}B\]
the result is \[I X=A^{-1}B\]
which is \[X=A^{-1}B\]

Answer 5

so.. how does this work on the numbers i have

Answer 6

find the inverse matrix A^-1
multiply that by B

you then get X

Answer 7

where A, B,X are defined in my first post