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Mathematics 6 Online
zarkam21 (zarkam21):

Help with three part question

zarkam21 (zarkam21):

zarkam21 (zarkam21):

OpenStudy (mrnood):

For part 1: The centre is the black dot. You can read the position in x on the horizontal axis You can read its position in y on the vertical axis Hint:You will need to assume tha tth ecentre lies on an exact 'integer' i.e. when you read down on th ex axis assume that it lies on one of the check marks When oyu have don the centre we can look at the radius.. post the (x,y) point of the centre here...

zarkam21 (zarkam21):

Well the point on the graph is (2,4)

zarkam21 (zarkam21):

So would that be the center

zarkam21 (zarkam21):

@MrNood

zarkam21 (zarkam21):

Hello? =)

OpenStudy (mrnood):

yes that is the centre now go horizontally to tht right of the centre and read the x value of the edge of the circle

zarkam21 (zarkam21):

5?

OpenStudy (mrnood):

Yes - good So whot is the distance from that point to the centre|?

zarkam21 (zarkam21):

1? cause 5-4

OpenStudy (mrnood):

no - you need to subtract the x value

zarkam21 (zarkam21):

so 5-2?

OpenStudy (mrnood):

yes - so the radius is 3 that is the first part done

zarkam21 (zarkam21):

so just to confirm for part 1, the center is at (2,4) and the radius is 3 units

OpenStudy (mrnood):

yes And that gives you all the answers fro part 2 as well

zarkam21 (zarkam21):

Okay r is 3 I know that

zarkam21 (zarkam21):

h is 2 and v 4?

OpenStudy (mrnood):

and it tells you that the centre is (h,v) and you know that is (2,4) Yes you are correct

OpenStudy (mrnood):

then just write thos 3 numbers into the general equation given to you in part 3

zarkam21 (zarkam21):

so for part 3, would it be (x-2)^2+(y-x)^2=3^2

OpenStudy (mrnood):

almost thre is a small error on your 'y' term'

zarkam21 (zarkam21):

Well there isn't anything to substitute for my y-term because the values are h,v

OpenStudy (mrnood):

I think you may have just made a typo - have a look you wrote x-h = x-2 do the same for the y-v term

zarkam21 (zarkam21):

(x-2)^2+(y-4)^2=3^2

OpenStudy (mrnood):

well done - that is correct h is the 'horizontal' and v is 'vertical' position of th ecentre this is the equation for ALL circles

zarkam21 (zarkam21):

Thank you so much, I appreciate it.! =)

OpenStudy (mrnood):

NP Just remember - YOU did the work Have the confidence to use the same methods on other circle questions...

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