Question

Math help please!!!!!!!!!!!!!!!!!!!!

Answer 1

The figure below shows a square ABCD and an equilateral triangle DPC:

ABCD is a square. P is a point inside the square. Straight lines join points A and P, B and P, D and P, and C and P. Triangle DPC is an equilateral triangle.

Ted makes the chart shown below to prove that triangle APD is congruent to triangle BPC:

Statements Justifications
In triangles APD and BPC; DP = PC Sides of equilateral triangle DPC are equal
In triangles APD and BPC; AD = BC Sides of square ABCD are equal
Angle ADC = angle BCD = 90° so angle ADP = angle BCP = 30°
Triangles APD and BPC are congruent SAS postulate


Which of the following completes Ted's proof?
In square ABCD; angle ADC = angle BCD
In square ABCD; angle ADP = angle BCP
In triangles APD and BPC; angle ADC = angle BCD
In triangles APD and BPC; angle ADP = angle BCP

Answer 2

@mathstudent55 Could you please help me?

Answer 3

I think C or D

Answer 4

Is there a place shown where the statement goes?

Answer 5

No actually I have to figure out that

Answer 6

Look at the last statement.
The proof uses SAS to prove two triangles congruent.

Answer 7

Ok

Answer 8

We can go over the proof that is written and see which parts of the triangles are shown to be congruent.
We must have a pair of sides, a pair of angles and another pair of sides.
Also, the pair of congruent angles must be inside the two pairs of congruent sides to use SAS.

Answer 9

ok

Answer 10

Let's go through each step of the proof an see which pairs of corresponding parts (sides or angles) we can mark as congruent.

Answer 11

1. In triangles APD and BPC; DP = PC 1. Sides of equilateral triangle DPC are equal

Answer 12

Ok