Question

plz help will medal
−3−3/4(c−4)=5/4
answers
2
-5/3
-15/16
-11

Answer 1

\[\frac{-3-3}{4(c-4)}=\frac{5}{4}\]first let's try to get the part with \(c\) alone, so:\[(-3-3)\div\frac{5}{4}=4(c-4)\]

Answer 2

-3-3 is -6:\[-6\div\frac{5}{4}=4(c-4)\]Dividing by a fraction also means multiplying by its reciprocal (the fraction flipped around):\[-6\times\frac{4}{5}=4(c-4)\]\[\frac{-24}{5}=4(c-4)\]

Answer 3

Distributing the 4(c-4):\[-\frac{24}{5}=4c-4(4)\]\[-\frac{24}{5}=4c-16\]\[-\frac{24}{5}+16=4c\]

Answer 4

Now isolate the \(c\).
A hint... \(16=\large{\frac{80}{5}}\)

Answer 5

16

Answer 6

16=16

Answer 7

What?

Answer 8

You can't add -24/5 and 16 without converting 16 to fractional form.

Answer 9

-24/5+4=c
i really dont get the way you doing it

Answer 10

Is this the equation?\[\frac{-3-3}{4(c-4)}=\frac{5}{4}\]

Answer 11

\[-3- \frac{ 3 }{ 4}(c-4)= \frac{ 5 }{ 4 }

Answer 12

I guess you could also do this:\[(-3-3)\times4=5\times[4(c-4)]\]

Answer 13

You can always do cross multiplication I guess. I'm not sure what your original problem was so I can't really help you.

Answer 14

\[-3-\frac{ 3 }{ 4 }(c-4)=\frac{ 5 }{ 4}\]
is my problem

Answer 15

My suggestion is to first multiply both sides by 4 to get rid of all fractions.

Answer 16

Can you do that and show what you get?

Answer 17

but im stiil gettin fractions

Answer 18

Let me show you.

Answer 19

\(\color{red}{4}[-3-\dfrac{ 3 }{ 4 }(c-4)]=\color{red}{4}(\dfrac{ 5 }{ 4})\)

See the red 4 on each side?
Each side is being multiplied by 4.

Answer 20

The right side is simply 4 * 5/4, which is 4/1 * 5/4.

\(\color{red}{4}[-3-\dfrac{ 3 }{ 4 }(c-4)]=\color{red}{\dfrac{4}{1}}(\dfrac{ 5 }{ 4})\)

\(\color{red}{4}[-3-\dfrac{ 3 }{ 4 }(c-4)]=\color{red}{\dfrac{\cancel 4}{1}}(\dfrac{ 5 }{ \cancel 4})\)

\(\color{red}{4}[-3-\dfrac{ 3 }{ 4 }(c-4)]=\color{red} 5\)

You see how the right side simplifies to only 5?

Answer 21

so dose 3/4 become 3 to

Answer 22

Yes, 3/4 becomes just 3 when you multiply by 4, but on the left side, you are multiplying 4 by a quantity, so you need to use the distributive property.

Answer 23

Let's work on the left side now.

\(\color{red}{4}[-3-\dfrac{ 3 }{ 4 }(c-4)]=5 \)

Answer 24

so the equation is
-3-3(c-4)=5

Answer 25

\(\color{red}{4}[-3-\dfrac{ 3 }{ 4 }(c-4)]=5 \)

Distribute the 4:

\(\color{red}{4}(-3)-\color{red} 4 \times\dfrac{ 3 }{ 4 }(c-4)]=5 \)

See how the 4 multiplies both terms?

Answer 26

Now we do each multiplication by 4.
You did the second one correctly, but you can;t forget the first one.

Answer 27

-12-3(c-4)=5
this

Answer 28

\(\color{red}{4}(-3)-\color{red} 4 \times\dfrac{ 3 }{ 4 }(c-4)=5 \)

\(\color{red}{-12}-\color{red}{3}(c-4)=5 \)

Answer 29

Correct.
Now you need to distribute the -3 through the parentheses.

Answer 30

\[-12-3c-12=5\]

Answer 31

Be careful with the signs.
You are multiplying each number in the parentheses by NEGATIVE 3.

Answer 32

\(-12 - 3(c - 4) = 5\)

\(-12 - 3[c + (- 4)] = 5\)

\(-12 - 3 \times c + (-3)(-4) = 5\)

Answer 33

\(-12 - 3 c + 12 = 5\)

Answer 34

-3 * c = -3c
-3 * (-4) = +12 <--- be careful with this multiplication

Answer 35

ok yeah cuz
negative * negative = positive

Answer 36

correct

Answer 37

Now, combine like terms on the left side.
Add -12 and 12 on the left side.
What do you get?

Answer 38

0

Answer 39

they cancel out

Answer 40

Good. That is correct.

You have this left:

\(- 3 c = 5\)

Solve for c.

Answer 41

c=-5/3

Answer 42

Correct.

Answer 43

thx

Answer 44

yw