Question

calc help please

Answer 1

So you found an inflection point, cool.
How bout extreme values?

\(\large\rm 0=3x^2-6x+6\)
\(\large\rm x=?\)

Answer 2

the critical points??.

Answer 3

Yes.

Answer 4

there cant be a critical point

Answer 5

There can't be a critical point because of the plus six.

Answer 6

You're right, there are not critical points,
But I'm not sure what you mean by `because of the plus six`.

Answer 7

well, even if you get a 0 for the other terms, you will get +6 at the end.
I know it is not the same for when you factor it, but I tried factoring it and it did not work,

Answer 8

So you figure it has sort of like a y-intercept of 6 type of thing going on? Careful! That line of thinking could get you into trouble! :)

Take for example: \(\large\rm x^2+2x+1\)
Just because it has a +1 on the end doesn't guarantee that it won't cross the x-axis. This standard form doesn't tell us a lot.

If factoring doesn't work, you should try using your Quadratic Formula.
But you'll just end up with complex roots in this case.

Answer 9

Do you need help sketching the graph? :o

Answer 10

yes..

Answer 11

So we can start with the inflection point I guess.