Question

Simplify square root parenthesis 1 minus sine theta parenthesis times parenthesis 1 plus sine theta parenthesis.

Answer 1

@MrNood
@phi
please help!!!!

Answer 2

\[\sqrt{(1-\sin \theta)(1+\sin \theta)}\]

Answer 3

idk how to solve it!!!

Answer 4

A - ±sinθ
B - cos θ
C- ±tan θ
D- \[\sqrt{\sin}\]

Answer 5

theta, sqrt sin theta for D

Answer 6

@princesskitty01

Answer 7

do you know the "pattern"
(a-b)(a+b) = a^2 - b^2

(You can use FOIL to show this is true)

anyway, if you use that, what does the inside of the square root become ?

Answer 8

I don't know that doesn't make sense to me..... @phi

Answer 9

@DivineSolar

Answer 10

it should.
You should have learned how to factor a "difference of squares"
i.e. x^2 -4 factors into (x-2)(x+2)

you should also have learned how to multiply
(x-y)(x+y) to get x^2 - y^2

or if all that is mysterious
you should know how to distribute
for example

A(1+ sin) = A + A sin
now if A is in fact (1-sin)
we get
1-sin+ (1-sin)*sin
now distribute the 2nd part:
1-sin + sin - sin*sin
or
1 - sin^2

Answer 11

ok that I understand, so would the answer be- \[\sqrt{\sin \theta}\] ???? @phi

Answer 12

wait no it wouldn't because the theta would have been cancled out, would it actually be +- sin????

Answer 13

how did you get just sin ? (btw, I'm leaving out the theta because it's too hard to type)

re-read what I posted. the inside is not just sin

Answer 14

you should get
\[ \sqrt{1 - \sin^2 \theta }\]

Answer 15

and that can be simplified using
sin^2 + cos^2 = 1
which means
cos^2 = 1 - sin^2

Answer 16

ohhhhhhhhh, ok, I understand that

Answer 17

can you help me with one other problem? I just want to make sure I got it correct or not

Answer 18

first, what did you get for an answer to this question ?

Answer 19

cos

Answer 20

right.....?......

Answer 21

yes

Answer 22

awesome can u help me with one more/?? @phi