Can someone help me with a Geometry question? Picture in chat.
For question number 8, all we need to do is solve for the surface area. Looking at this equilateral triangle, there are two congruent triangles, two congruent rectangles, and one rectangle off on his own with the dimensions 10x15
yes...and
|dw:1477672073844:dw|
At what part do you need help?
Do you know how to find each of the sides?
OK, so I found each of the sides already but the answer i got is wrong
Do i just add them up afterwards?
Yes
Do you want me to find all the sides, and see if our values match up?
yes, thank you
|dw:1477672671047:dw| Checklist: Rectangle 1: 150un^2 Rectangle 2 and 3: Triangle 1 and 2: The first one our checklist is easy, we just multiply 10 by 15 for 150. Rectangle 2 and 3 is where it gets difficult, as we need it's width, which is not displayed. Looking at our right triangle though, it's hypotenuse is the rectangles width, and we have the two side lengths, therefore we can solve for it using Pythagorean's Theorem. Note: Pythagorean's Theorem only works on right triangles, therefore if you did 8.7^2 + 10^2 = c^2, you would be wrong. The proper use of the theorem would be 8.7^2 + 5^2 = c^2 as I know that the line representing the height, bisects the 10, into two 5's. \[8.7^2 + 5^2 = c^2\] \[75.69 + 25 = c^2\] \[100.69 = c^2\] Get the square root of both sides, and we get \[c = 10.0344406919 \rightarrow 10.03\] Lets round..
\[10.03 \times 15 \times 2 = 300.9 un^2\]
you should be opening more qustions so that the person answering can get the medals he/she deserves
what o.O
so the answer is 624?
Checklist: Rectangle 1: 150un^2 Rectangle 2 and 3: 300.9un^2 Triangle 1 and 2: I now only have one more item on the list, which is quite simple Solving for the two surface areas of the triangle is just a matter of \[8.7 \times 10 = 87\] Triangle 1 and 2 = 87 Whilst the formula is \[A = \frac{ hb }{ 2 }\] We forgo the division so we don't have to repeat it, as the triangles have the same dimensions Add up 150, 300.9 and 87, and we get \[537.9 un^2\]
Oh, okay
Thank you so much!
No problem :)
Join our real-time social learning platform and learn together with your friends!