Question

What is the original function of this derivative?

Answer 1

\large f'(x)=\frac{ (\cos(x))^2(x^2-x-2.1) }{ \sqrt{x^2+1} }\]

Answer 2

Ok, something is wrong with my LaTex

Answer 3

\[\large f'(x)=\frac{ (\cos(x))^2(x^2-x-2.1) }{ \sqrt{x^2+1} }\]

Answer 4

Wat, how did you do that? I need to learn how to use latex

Answer 5

i dunno i just copy/pasted what you had haha

yeah that is nt a fun integral :(

Answer 6

Can you just post the answer I can use a calcualtor.

Answer 7

I don't know how to sue integral on my calculator.

Answer 8

calculator can only approximate a definite integral, you have to put in limits

Answer 9

waat can you please post the antiderivative of this function.

Answer 10

in other words there is no way of taking the antiderivative

Answer 11

Ok, I want to find the max/min location of the original function from the interval -6 <= x <= 7
What is the answer to this?

Answer 12

oh that we can do.... set derivative function equal to 0 to find max/min

hmm but how to plug critical values into original...

Answer 13

I just need the x values for max/min

Answer 14

just wolfram alpha it

Answer 15

So just cheat it?

Answer 16

How do I wolfram alpha this?

Answer 17

https://www.wolframalpha.com/input/?i=(cos%5E2+x)+(x%5E2+-x-2.1)+%3D+0

Answer 18

By the way your LaTeX didn't format properly because you're missing the \[ in front.

Answer 19

here is wolfram trying to find antiderivative

https://www.wolframalpha.com/input/?i=integrate+(cos%5E2+x)+(x%5E2+-x-2.1)%2Fsqrt(x%5E2%2B1)+dx

Answer 20

Ok thanks guys, so wolframalpha can't even calculate the antiderivative.