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Mathematics 15 Online
OpenStudy (sam_pi):

for the following problem determine whether the equation represents continues growth or decay or neither, explain y=150(e)^3.25/t I know it can’t equal to zero , and if you graph this we will have a vertical asymptote at zero so I think the answer is Neither growth nor decay but I still don’t understand how it can still be considered an exponential function without growth or decay. do you know any real application where we would need to divide the exponent with a variable?

OpenStudy (sooobored):

you know the limit as t approaches 0, what happens to the limit as t approaches infinity? just looking at the 3.25/t part

OpenStudy (3mar):

It is obvious that this function is always decaying; because the the y-value decreases as x-value increases!

OpenStudy (3mar):

@sam_pi

OpenStudy (sam_pi):

no the function should be written as\[y=150(e)^{\frac{ 3.25 }{ t }}\]

OpenStudy (3mar):

Oh sorry One minute, please!

OpenStudy (3mar):

https://www.desmos.com/calculator/6flbpesw1c It is also decays because y decreases when x increases! Got it?

OpenStudy (3mar):

@sam_pi

OpenStudy (sam_pi):

so when it will be neither ?

OpenStudy (sam_pi):

and do you know when a problem like this would be needed ? most other problems I've seen you need to multiplay the variable with the exponent not divide it

OpenStudy (sam_pi):

**multiply

OpenStudy (3mar):

When it is a constant value like y=5 or even has a local maxima or minima! |dw:1477768899962:dw|

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