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calculate the volume of 10.0 mol L-1 nitric acid solution required to prepare 500.0 mL of 0.500 mol L-1 solution
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been a while since chem, but isnt the dilution someting like concentration 1 * Volume 1 = Concentration 2 * Volume 2
\[M_1V_1=M_2V_2\]
Make sure you have concentration in units of molarity (mol/L) and volume in units of Liters.
could you guys solve this now?
you use the formula from above, keeping units consistent, using liters concentration 1 * Volume 1 = Concentration 2 * Volume 2 10.0 mol/L * (Volume 1) = 0.500 mol/L * 0.500 L 10.0 * V = 0.500 * 0.500
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