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Mathematics 14 Online
OpenStudy (steve816):

What is the antiderivative of

OpenStudy (steve816):

\[\Huge e^{2x}\]

OpenStudy (518nad):

|dw:1477883301213:dw|

OpenStudy (steve816):

How did you figure that out?

OpenStudy (steve816):

It is chain rule right?

OpenStudy (sshayer):

\[\int\limits e^{2x}dx=\frac{ e^{2x} }{ 2 }+c\]

OpenStudy (danjs):

you can make a substition for u=2x, du = 2, and solve that way the integral of e^u is the same e^u

OpenStudy (danjs):

u=2x, du=2 dx, dx=du/2 \[\large \frac{ 1 }{ 2 } \int\limits e^u*du=\frac{ 1 }{ 2 } e^u+C\]

OpenStudy (steve816):

Ok I see, thank you.

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