The value of X in a system
Try turning each of these equation into slope-intercept form. \(\LARGE\bf{3x+2y=8}\) Subtract 3x. \(\LARGE\bf{2y = -3x + 8}\) Divide by 2. \(\LARGE\bf{y=\frac{3}{2}x+4}\) ~~~~~ \(\LARGE\bf{2x+3y=2}\) Subtract 2x. \(\LARGE\bf{3y=2x + 2}\) Divide 3. \(\LARGE\bf{y = -\frac{2}{3}x+\frac{2}{3}}\)
My mistake i ment to say i now its not C
What is the value of the x variable in the solution to the following system of equations? 3x + 2y = 8 2x + 3y = 2 4 −2 x can be any number as there are infinitely many solutions to this system There is no x value as there is no solution to this system
Ok so lets solve this by using substitution. Since the first equation is already in slope-intercept form we would plug that in to the second equation. \(\huge\bf{2x+3(-\frac{3}{2}x+4)=2}\) Simplify.
So it would Be B?
@563blackghost
Not quite. \(\huge\bf{2x+3(-\frac{3}{2}x+4)=2}\) Distribute. \(\huge\bf{2x-\frac{9}{2}x+12=2}\) Combine. \(\huge\bf{-\frac{5}{2}x + 12 = 2}\) Subtract 12. \(\huge\bf{-\frac{5}{2}x=-10}\) Divide `-5/2` \(\huge\bf{x=4}\)
Sorry took so long to reply.
thanks
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