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Vocaloid (vocaloid):
I'm a bit rusty with integration - question below
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Vocaloid (vocaloid):
\[\int\limits_{ }^{ } \frac{ 4x }{ x^2 + \frac{ 1 }{ x } }\]
Vocaloid (vocaloid):
don't want a direct answer, I just want to know where to start
Vocaloid (vocaloid):
*should be a dx added into the equation
zepdrix (zepdrix):
It looks like it might be a simple u-substitution hidden in disguise.
Try multiplying top and bottom by x, what happens?
Vocaloid (vocaloid):
\[\int\limits_{ }^{ }\frac{ 4x^2 }{ x^3 + 1 }\]
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Vocaloid (vocaloid):
so I'm guessing I would let u = x^3 + 1
then that gives me du = 3x^2
OpenStudy (sweetburger):
yes, perfect
OpenStudy (coolor):
*du=3x^2(dx)
zepdrix (zepdrix):
Bottom is a cubic, top is a square,
hmm that works out nicely! :)
OpenStudy (coolor):
^`
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zepdrix (zepdrix):
\[\large\rm du=3x^2dx\]You could take a couple simple steps and turn the 3 into a 4 so it matches up perfectly with your numerator.
Vocaloid (vocaloid):
right, multiply by 4/3
Vocaloid (vocaloid):
(4/3)*ln(x^3+1)?
zepdrix (zepdrix):
Yayyy good job \c:/
OpenStudy (coolor):
don't forget the constant "c"
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Vocaloid (vocaloid):
thank you both, I just started differential equations >>
zepdrix (zepdrix):
Ooo fun stuff!
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