Question

Help?

Answer 1

What did you pick?

Answer 2

Im still trying to understand the question

Answer 3

Take your time.

Answer 4

have you heard of pythagoras theorem?

Answer 5

Im look at this rn, is this it?

Answer 6

Of course I have, but what about you?

Answer 7

it was @Book

Answer 8

yes that is the principle to be used

Answer 9

Then yes but idk how to find a... i see theres a 49 in the corner would that be used as a?

Answer 10

you also need to apply trigonometry

Answer 11

have you heard of SOHCAHTOA

Answer 12

kinda

Answer 13

that image shows the trigonometric ratios

Answer 14

we want to get the length of the plank, which can be said to be c in the second diagram, and hypotenuse in the third diagram

Answer 15

we now need to use what we have to get what we need

Answer 16

we have the distance between the foot of the plank and the wall as 3 ft and that is the 'opposite' because it is facing opposite the angle 49 degrees

Answer 17

so we look for the trig. ratio comparing opposite and hyptoenuse, which is sin(A) The A here is 49

Answer 18

so\[\sin49=\frac{ 3 }{ hyp }\]

Answer 19

mk

Answer 20

using a calculator or four figure table, sin49 is approximately equal to 0.8or 8/10. So\[\frac{ 8 }{ 10 }=\frac{ 3 }{ hyp }\]
\[8hyp=30\]
\[hyp=30/8=3.75\]
That is 3.8ft to the nearest tenth

Answer 21

do you understand

Answer 22

Yes ty

Answer 23

Would that answer both questions?

Answer 24

you can use the same format to solve for the second question

Answer 25

hmm ok

Answer 26

Could u help me out on part b?

Answer 27

ok

Answer 28

since the length of the wall is 'adjacent' because it is close or 'adjacent' to the angle in focus

Answer 29

now since we know both the hypotenuse and the opposite, there are three things we can use
1. \[a^{2}+b^{2}=c^{2}\]

Answer 30

sorry gotta go

Answer 31

ok..

Answer 32

If I may help?

Answer 33

yes please

Answer 34

Can we start in new post, please?

Answer 35

sure

Answer 36

Thank you.