Question

Hello, could someone help with differential equations?

Answer 1

This is the equation: \[2y'' - y' + \frac{ 1 }{ 2 }y = \frac{ 5 }{ 2 }x^{2}\]

Our answer is A = 5, B = -36, and C = 54

Is that right?

Answer 2

Ugh the problem stopped. The rest of the original equation is 5/2x^2 - 8x + 11

Answer 3

A B and C? Whu? :d

Answer 4

one sec

Answer 5

y = ax^2 + bx + c; y' = 2ax + 6; y'' = 2a

Answer 6

Oh so you mean the form that the particular solution will take on,\[\large\rm y=ax^2+bx+c\]\[\large\rm y'=2ax+b\]\[\large\rm y''=2a\]Yes, that seems right.

Did you already find the homogeneous solution to your differential equation?\[\large\rm 2y''-y'+\frac12y=0\]

Answer 7

Oh noessss :O Where'd you go?
Confused?

Answer 8

:p

Answer 9

k go on and add homogenous soln to ur particular