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Hello, could someone help with differential equations?
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This is the equation: \[2y'' - y' + \frac{ 1 }{ 2 }y = \frac{ 5 }{ 2 }x^{2}\] Our answer is A = 5, B = -36, and C = 54 Is that right?
Ugh the problem stopped. The rest of the original equation is 5/2x^2 - 8x + 11
A B and C? Whu? :d
one sec
y = ax^2 + bx + c; y' = 2ax + 6; y'' = 2a
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Oh so you mean the form that the particular solution will take on,\[\large\rm y=ax^2+bx+c\]\[\large\rm y'=2ax+b\]\[\large\rm y''=2a\]Yes, that seems right. Did you already find the homogeneous solution to your differential equation?\[\large\rm 2y''-y'+\frac12y=0\]
Oh noessss :O Where'd you go? Confused?
:p
k go on and add homogenous soln to ur particular
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