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Mathematics 9 Online
OpenStudy (steve816):

How can I possibly visually interpret this?

OpenStudy (inkyvoyd):

no

OpenStudy (steve816):

So I know that \[2^3 = 2 * 2 * 2\]or 2 multiplied by itself 3 times but what is \[\large 2^{3.4}\] I can't grasp the concept of raising something to a decimal.

OpenStudy (catpidigm):

is it 2*2*2*2.4 idk

OpenStudy (steve816):

^Nice try

OpenStudy (inkyvoyd):

what about 2+2 vs 2*2.4?

OpenStudy (steve816):

Well, I would interpret that is 2.4 + 2.4 = 4.8

OpenStudy (inkyvoyd):

what about 2.4*2.4?

OpenStudy (catpidigm):

or 2.4*2.4*2.4 ???

OpenStudy (steve816):

^That is \[2.4^3\]

OpenStudy (catpidigm):

oh

OpenStudy (agent0smith):

Have you tried doing it with fractional exponents instead of decimals?

OpenStudy (steve816):

Fractions? Haven't tried that for this case.

OpenStudy (agent0smith):

\[\Large 2^{3.4} = 2^{3+ \frac{ 2 }{5 }}\]

OpenStudy (sooobored):

how about \[2^{3.4}=2^{3.4/1}=2^{34/10}\]

OpenStudy (inkyvoyd):

you can actually use the laws of exponents. 2^2.4 = 2^2*2^0.4... or as agent smith said, you get \(\sqrt[5]{2^{12}}\)

OpenStudy (agent0smith):

\[\Large 2^{3.4} = 2^{3}*2^{ \frac{ 2 }{5 }} = 2^3*\sqrt[5]{2^2}\]

OpenStudy (inkyvoyd):

tbh this is all way easier to visualize if you understand logarithsm...

satellite73 (satellite73):

the fact is that there is a specific meaning to exponential, which is not "repeated multiplication" at this point it might not make sense, but the definition of \(b^x\) is \[\huge b^x=e^{x\ln(b)}\]

OpenStudy (steve816):

@inkyvoyd I do know logarithms...

OpenStudy (inkyvoyd):

there's a difference between knowing how to manipulate logarithmic expressions and actually being able to visualize and understand what logarithms are doing. Have you ever played with a slide rule?

satellite73 (satellite73):

with this you can make sense out of say \[\huge 5^{\sqrt2}=e^{\sqrt{2}\ln(5)}\]

OpenStudy (steve816):

@agent0smith Ah, I see how you got that.

OpenStudy (steve816):

Okee, I think reading over this, cleared up some of my confusion. Thanks to all those who replied!

OpenStudy (bonnieisflash1.0):

hey @agent0smith want to be friends

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