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Find the average rate of change 50x/x+3 on (2,7)
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@emac
your equation is \[y=\frac{ 50x }{ x+3 }\] The rate of change of a function is the first derivative of this function \[\frac{ dy }{ dx }=y'=y=\frac{ (x+3)*[50]-50x(1) }{ (x+3)^2 }=\frac{ 150 }{ (x+3)^2 }\]
To find the derivative at (2,7), substitute with x=2: \[y'=\frac{ 150 }{ (2+3)^2 }=\frac{ 150 }{ (5)^2 }=\frac{ 150 }{ 25 }=6\] That is it! I hope that helps!
yes thank you!!
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