a drugist has two solutions of alcohol. one is 25% alcohol. the other is 45% alcohol. he wants to mix these two solutions to get 36 ounces that will be 30% alcohol. how many ounces of each of these two solutions should he mix together?
Set up two equations A) x + y = 36 B) .25x + .45y = (.30 * 36) Then solve for x and y
Do you know how to solve for x and y?
not really, are you supposed to multiply .25 to the first equation?
That would be one way but I would multiply equation "B" by minus 4
where did the minus 4 come from?
We'd want to have it so that one of the unknowns could be eliminated. Multiplying equation "B" by -4 would make it B) -x -1.8Y = -43.20 When we add that to equation "A" the "x" term gets eliminated
Do you want to see how that's done?
yes please
A) x + y = 36 B) -x -1.8 y = -43.20 Adding both equations we get -.80y = -7.2
ohhh I see I kept multiplying the minus 4 to the a equation as well
so y would turn out to equal 9?
No you multiply equation B) .25x + .45y = (.30 * 36) by -4 and it becomes B) -x -1.8 y = -43.20 THen add it to equationA And yes "y" is nine!!!
and so to get x would you just do 36-9?
which is 27 but is that how id have to solve x?
That is exactly how it is done
So basically you need 27 ounces of 25% and 9 ounces of 45%
ok thank you so so much for helping me out! <3 :D
u r welcome
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