Question

Check my answer for one & help with another?

Answer 1

Sorry, I was not here!

Answer 2

The first one is correct!
for the second one, I am on it!

Sorry for being late!

Answer 3

no problem :)

Answer 4

Thanks

Answer 5

\[\frac{ d^2-9d+18 }{ d^2+2d-15 }=\frac{ (d-3)(d-6) }{ (d-3)(d+5) }=\frac{ d-5 }{ d+5 }\]
this is for the left-side ratio

ok?

Answer 6

ok..

Answer 7

For the right-side ratio:
\[\frac{ d^2-2d-8 }{ d^2+5d+6 }=\frac{ (d-4)(d+2) }{ (d+3)(d+2) }=\frac{ d-4 }{ d+3 }\]

Do you follow?

Answer 8

yes

Answer 9

\[\frac{ d-5 }{ d+5 }+\frac{ d-4 }{ d+3 }=\frac{ (d-5)(d+3)+(d-4)(d+5)}{ (d+5)(d+3) }\]

Answer 10

\[\frac{ d^2-9d+18 }{ d^2+2d-15 }=\frac{ (d-3)(d-6) }{ (d-3)(d+5) }=\frac{ d-6 }{ d+5 }\]

Sorry ... modification on the first fraction

my mistake

Answer 11

We will reach it now

Answer 12

\[\frac{ d-6 }{ d+5 }+\frac{ d-4 }{ d+3 }=\frac{ (d-6)(d+3)+(d-4)(d+5)}{ (d+5)(d+3) }\]


\[\frac{ (d-6)(d+3)+(d-4)(d+5)}{ (d+5)(d+3) }=\frac{ d^2+3d-6d-18+d^2+5d-4d-20 }{ (d+5)(d+3) }\]


\[\huge\frac{ 2d^2-2d-38 }{ (d+5)(d+3) }\]

That means you should pick B

By the way, there are two identical pair of choices. you notice that?

Answer 13

Yes, but they are both wrong so thats why I didn't mind it. Thanks though, I'm going to start another thread & could u check my answer for another problem?

Answer 14

"Yes, but they are both wrong" what do you mean?

Answer 15

Yes, I noticed that two answers are the same but I didn't mind them because they are wrong anyway.

Answer 16

My result I have gotten is wrong?

Answer 17

No haha you were right.. never mind lol I'm about to start another thread

Answer 18

Did you get what you were looking for?

This is what matters for me!

Answer 19

Thank you for the medal!