Question

if f is the antiderivative of the x^2/(1+x^5) such that f(1)=0, then f(4)= ?

Answer 1

\[\frac{ x^2 }{ 1+x^5 }\]

Answer 2

easy

Answer 3

help plss i've done it 3 times and can't get the right answer

Answer 4

So you want to compute \int x^2/(1+x^5) dx from 1 to 4.

g(x) = x^2 / (1+x^5) is strictly decreasing from 1 to 4 as you can check by dg/dx.

And g(1) = 1/2, g(2) = 4/33, g(3) = 9/244, g(4) = 16/1025.

If you're allowed to use the calculator, g(1.5) = 0.2618 as well.

So (a), (b) are obviously out. (c) is out because the area from 1 to 1.5 is already > 0.2618 * 0.5 = 0.13.

Finally, I believe (e) is an overestimate (you'll have to verify it yourself).

Answer 5

I think

Answer 6

does this help

Answer 7

wait where did u get that answer from?

Answer 8

school teacher y

Answer 9

lol it was a really fast response and u knew all the answer choices xD

Answer 10

ik right

Answer 11

so g(x) is what, the original function??

Answer 12

it is in what i said

Answer 13

is this a multiply chose

Answer 14

question

Answer 15

lol ur answer is straight off yahoo answers xD

Answer 16

do u know how to do these tho?

Answer 17

yes

Answer 18

i just ask my teacher and he said that

Answer 19

NOT ME

Answer 20

ok thx for the help

Answer 21

sure np

Answer 22

lol :)