Question

You apply a force of 17 N to a wheel with a radius of 0.75 m. If the axle has a radius of 6 cm, what is the output force, assuming the machine operates under ideal conditions?

2.13 N

76.5 N

212.5 N

12.75 N
@3mar

Answer 1

Do you have a graph or something?

Answer 2

no i dont

Answer 3

so what you got?

Answer 4

nothing but confused

Answer 5

really I need a figure because::
"a wheel with a radius of 0.75 m"
and
"the axle has a radius of 6 cm"

Answer 6

i dont have a figure

Answer 7

@3mar

Answer 8

@zepdrix

Answer 9

@Directrix

Answer 10

@mathmate

Answer 11

this is the only thing i have in the notes

Answer 12

@18jonea
The figure/illustration means a lot to clarify the situation!

Answer 13

so that helped?

Answer 14

@mathmate

Answer 15

"The figure/illustration means a lot to clarify the situation!"

THAT IS WHAT I WAS SAAAAAAAAAAAAAAAAYING

IT MAKES SENSE NOWWWWWWW

Answer 16

The force at the wheel will be transefered as it is to the output axle.
so the principle is
\[F_1*r_1=F_2*r_\]
where 1 stands for the moment at the wheel and 2 for the end axle

17*0.75=F_2*0.06

you find F_2

Answer 17

\[\huge F_1*r_1=F_2*r_2\]

Answer 18

Got it?

Answer 19

12.75= f2 *.06

Answer 20

12.75/.06= 212.5

Answer 21

correct?

Answer 22

@3mar

Answer 23

Correct!
I had it 212.5 N also

Answer 24

Thank you for your patience.

Answer 25

thank you!!!!

Answer 26

I really appreciate!

Answer 27

Thank you for the medal!

Answer 28

Any more questions?