Verify sec x(csc x − 2 sin x) = cot x − tan x ?
What is sec= to?
1/cos?
Yup! Now try distributing that into the parenthesis
sec x(csc x − 2 sin x) = 1/cosx (1/sinx - 2sin^2 x/?)
That's a terrible way to do it -_- But it works...Just look at that first unknown box...what do you think goes there? To make it match up with the left side
*Big hint there in the next step, you can see inside the parenthesis have been put over a common denominator*
sin(x) for the next two blanks?! Thank you!
Correct!
I'm confused how to get the third blank though
And the third box...they just multiplied in the 1/cos(x) into the parenthesis So we know 1 * the numerator is just the numerator But now that we know sin(x) is on the bottom...and that is being multiplied by cos(x)...what is our new denominator?
*Don't overthink it! :)
Is this an identity? Sorry, I am really bad at these problems because we just started with this in our class
Nope, no identity Haha reason why i said don't over think it :) What is cos(x) * sin(x)? Literally just cos(x)sin(x) That is your new denominator!
\[\sec x \left( \csc x-2\sin x \right)=\sec x \left( \frac{ 1 }{ \sin x }-2\sin x \right)\] \[=\sec x \left( \frac{ 1-2\sin ^2x }{ \sin x } \right)=\frac{ \cos ^2x+\sin ^2x-2\sin ^2x }{ \cos x \sin x }\] \[=\frac{ \cos ^2x-\sin ^2x }{ \cos x \sin x }=?\]
Lol yes as @sshayer has put above in a neater fashion :)
Oh wow! Lol okay thank you! So the 4th blank is the same?
So those 3,4 and 5 boxes should be easy for you to fill in
Indeed boxes 3 and 4 are the same
Box 5 is quite simple as well...
Got it! Thank you so much! I am so glad I found out about this website! Is it free all the time or is there like a trial first?
Free all the time! There was a system in place before where you could pay to get "Qualified helper assistance" but that has sense disappeared *For the moment* But yeah, it's a great resource for help!
^Ignore my bad grammar there XD *sense --> Since*
Awesome! Thanks again!!)
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