Where does the normal line ellipse x^2-xy+y^2=3 at a point (-1,1) intersect the ellipse a second time?
Illustrate by graphing the ellipse and the normal line.

Question

Where does  the normal line ellipse x^2-xy+y^2=3 at a point (-1,1) intersect the ellipse a second time?
Illustrate by graphing the ellipse and the normal line.

roguehamster2073 · Answer

Answer is A: Bees can communicate but not by spoken language.

issimplcalcus · Answer

My bad the normal line is 90 degrees to the point

issimplcalcus · Answer

So what you would do is find the dy/dx at (-1,1) then do the inverse of dy/dx to find the perpendicular or normal line

issimplcalcus · Answer

then you would find the equation using your new slope and set it equal to the eclipse to find the intersections

loser66 · Answer

Support!! when you have a new slope, then write out the equation of the line with that slope and the given point (1,1). Solve for y.
Replace that y to the curve of the ellipse to get x

Then replace back to the line or to the equation of the ellipse to get y.

loser66 · Answer

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loser66 · Answer

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loser66 · Answer

That is y = ..... something.

loser66 · Answer

Put this y back to ellipse to solve for x.

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