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Mathematics 11 Online
OpenStudy (moldybubblegum11):

Can someone help me find an easy way to do this. I will medal.

OpenStudy (moldybubblegum11):

@johnweldon1993 @agent0smith

OpenStudy (brokenstanzas):

I think you would multiply 25000 by 0.014 then add the product to 25000

OpenStudy (moldybubblegum11):

25000 * .014 is 350. and 25000 + 350 is 25350

OpenStudy (moldybubblegum11):

should i keep multiplying the product by .014?

OpenStudy (brokenstanzas):

Yep. So you would now multiply 25350 by .014 then keep going until you do it fifteen times. There might be a quicker way to do it but I'm not sure how

OpenStudy (moldybubblegum11):

doesn't interest percentage grow each year?

OpenStudy (brokenstanzas):

No. Interest is usually a fixed rate

OpenStudy (moldybubblegum11):

okay

OpenStudy (moldybubblegum11):

is there an easier way to do this?

OpenStudy (brokenstanzas):

Okay I found a formula for this. Starting amount x interest rate x time

OpenStudy (agent0smith):

Just use the compound interest formula. \(\Large A = P\left( 1+ \frac{ r }{n} \right)^{nt}\) http://i.stack.imgur.com/8pvNI.png

OpenStudy (moldybubblegum11):

thanks

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