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Mathematics 12 Online
OpenStudy (song_of_the_sole):

help please will medal and fan

OpenStudy (song_of_the_sole):

what is the following solution of the following system 3x+3y=10 -9x-9y=-30

satellite73 (satellite73):

what happens if you multiply the first equation by \(*-3\) all the way across?

OpenStudy (song_of_the_sole):

what do you mean? @satellite73

satellite73 (satellite73):

multiply all terms in the first equation by \(-3\)

OpenStudy (song_of_the_sole):

wait im a little confused what would that look like?

satellite73 (satellite73):

what does minus three look like?

OpenStudy (song_of_the_sole):

-3

satellite73 (satellite73):

ok so multiply \[-3(3x+3y)=10\times (-3)\]

OpenStudy (song_of_the_sole):

so 9x+9=-30

satellite73 (satellite73):

no

OpenStudy (song_of_the_sole):

-30x

OpenStudy (harman.singh):

Hey @song_of_the_sole , I helped someone with a similar question earlier. You can have a read of the conversation if you like. Link: http://openstudy.com/study#/updates/581924f7e4b03ac563213d41

OpenStudy (song_of_the_sole):

thank you but in order for me to understand i need someone to help me like step by step @harman.singh like how @satellight73 is

OpenStudy (song_of_the_sole):

but if u can help me step by step please do

OpenStudy (harman.singh):

okay. In general, do you know how to use the elimination method to solve a set of equations?

OpenStudy (song_of_the_sole):

kinda but need to refresh but im sure ill catch on as we go

OpenStudy (harman.singh):

The idea is to have a common value in both of the equations so they can cancel out when subtracting. Have a quick read of this webpage if you need to refresh on it: http://mathsfirst.massey.ac.nz/Algebra/SystemsofLinEq/EMeth.htm Once you understand it, it will be easier for me to help you with your question

OpenStudy (song_of_the_sole):

okay so how should we start

OpenStudy (harman.singh):

So here are our two equations 3x+3y=10 -9x-9y=-30 Lets begin by multiplying each of the equations by a number which would give us the same x value in both equations

OpenStudy (harman.singh):

Lets aim to have -9x in both of the equations

OpenStudy (song_of_the_sole):

so 3

OpenStudy (harman.singh):

Think again. Multiplying 3 by the first equation would give us 9x. But we want -9x

OpenStudy (song_of_the_sole):

-3

OpenStudy (harman.singh):

Yes, thats correct. Now multiply the whole equation by -3 and what do you get? -3(3x+3y=10) = ?

OpenStudy (song_of_the_sole):

-9x-9y=10

OpenStudy (harman.singh):

You also need to multiply the 10 by -3. So it now looks like -9x-9y=-30

OpenStudy (song_of_the_sole):

oh sorry

OpenStudy (song_of_the_sole):

so now what?

OpenStudy (harman.singh):

Now that we have managed to get the same coefficients for the x value, we can subtract them from one another. It would look like: -9x-9y=-30 -(-9x-9y=30) What do you get after subtracting them from one another?

OpenStudy (song_of_the_sole):

what do you mean?

OpenStudy (harman.singh):

Have a look at that website again. See how they did step 2. Do you understand that part?

OpenStudy (song_of_the_sole):

not really

OpenStudy (harman.singh):

Once they had it in this order, 6x + 9y = 24 -(6x + 4y = 14) They multiplied the bottom equation by - (negative) to expand the bracket So it became -6x-4y=-14. Good so far? Once I write the equations again, they look like 6x+9y=24 -6x-4y=-14 Now solve each of the values one by one 6x take away 6x is 0 (zero) so they cancel out. You are now left with 9y=24 -4y=-14 9y take away 4y gives you 5y. and 24 take away 14 gives you 10 Now we are left with 5y=10 Rearranging this we can find the value for y y=10/5 Therefore y=2 Do you understand what I explained? We have to use a similar approach to our question

OpenStudy (harman.singh):

Let me know if you want me go over anything specific from the above example. It might look confusing at first

OpenStudy (song_of_the_sole):

okay so how should i do this for my equation... so sorry but i really need to speed this up because im about to leave to get dropped off at school

OpenStudy (harman.singh):

alright I will make it quick

OpenStudy (harman.singh):

-9x-9y=-30 -(-9x-9y=-30) After expanding the brackets, we have -9x-9y=-30 9x+9y=30 -9x + 9x = 0 (so they cancel out) -9y + 9y = 0 (so they cancel out) -30 + 30 = 0 (so they cancel out) So really, you are left with 0=0 This means that your set of equations have no solutions. What a bugger :)

OpenStudy (song_of_the_sole):

and thats it?

OpenStudy (harman.singh):

Yes, thats it :)

OpenStudy (harman.singh):

This one was a bit different as it had no solution. But if you understood the procedure, you will be able to solve equations that do have a solution. If you get stuck, refer to the website or ask here. Good luck!

OpenStudy (harman.singh):

Correction: I wrote that the set of equation has no solutions. That's incorrect. I should have said the equations have infinite solution. My apologies. For future reference, - when the answer is 0=0 , it has infinite solutions - when the answer is something like 0=5, it has no solutions - when the final answer for the the coordinates is something like (5,6), it has one solution

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