help please will medal and fan
what is the following solution of the following system 3x+3y=10 -9x-9y=-30
what happens if you multiply the first equation by \(*-3\) all the way across?
what do you mean? @satellite73
multiply all terms in the first equation by \(-3\)
wait im a little confused what would that look like?
what does minus three look like?
-3
ok so multiply \[-3(3x+3y)=10\times (-3)\]
so 9x+9=-30
no
-30x
Hey @song_of_the_sole , I helped someone with a similar question earlier. You can have a read of the conversation if you like. Link: http://openstudy.com/study#/updates/581924f7e4b03ac563213d41
thank you but in order for me to understand i need someone to help me like step by step @harman.singh like how @satellight73 is
but if u can help me step by step please do
okay. In general, do you know how to use the elimination method to solve a set of equations?
kinda but need to refresh but im sure ill catch on as we go
The idea is to have a common value in both of the equations so they can cancel out when subtracting. Have a quick read of this webpage if you need to refresh on it: http://mathsfirst.massey.ac.nz/Algebra/SystemsofLinEq/EMeth.htm Once you understand it, it will be easier for me to help you with your question
okay so how should we start
So here are our two equations 3x+3y=10 -9x-9y=-30 Lets begin by multiplying each of the equations by a number which would give us the same x value in both equations
Lets aim to have -9x in both of the equations
so 3
Think again. Multiplying 3 by the first equation would give us 9x. But we want -9x
-3
Yes, thats correct. Now multiply the whole equation by -3 and what do you get? -3(3x+3y=10) = ?
-9x-9y=10
You also need to multiply the 10 by -3. So it now looks like -9x-9y=-30
oh sorry
so now what?
Now that we have managed to get the same coefficients for the x value, we can subtract them from one another. It would look like: -9x-9y=-30 -(-9x-9y=30) What do you get after subtracting them from one another?
what do you mean?
Have a look at that website again. See how they did step 2. Do you understand that part?
not really
Once they had it in this order, 6x + 9y = 24 -(6x + 4y = 14) They multiplied the bottom equation by - (negative) to expand the bracket So it became -6x-4y=-14. Good so far? Once I write the equations again, they look like 6x+9y=24 -6x-4y=-14 Now solve each of the values one by one 6x take away 6x is 0 (zero) so they cancel out. You are now left with 9y=24 -4y=-14 9y take away 4y gives you 5y. and 24 take away 14 gives you 10 Now we are left with 5y=10 Rearranging this we can find the value for y y=10/5 Therefore y=2 Do you understand what I explained? We have to use a similar approach to our question
Let me know if you want me go over anything specific from the above example. It might look confusing at first
okay so how should i do this for my equation... so sorry but i really need to speed this up because im about to leave to get dropped off at school
alright I will make it quick
-9x-9y=-30 -(-9x-9y=-30) After expanding the brackets, we have -9x-9y=-30 9x+9y=30 -9x + 9x = 0 (so they cancel out) -9y + 9y = 0 (so they cancel out) -30 + 30 = 0 (so they cancel out) So really, you are left with 0=0 This means that your set of equations have no solutions. What a bugger :)
and thats it?
Yes, thats it :)
This one was a bit different as it had no solution. But if you understood the procedure, you will be able to solve equations that do have a solution. If you get stuck, refer to the website or ask here. Good luck!
Correction: I wrote that the set of equation has no solutions. That's incorrect. I should have said the equations have infinite solution. My apologies. For future reference, - when the answer is 0=0 , it has infinite solutions - when the answer is something like 0=5, it has no solutions - when the final answer for the the coordinates is something like (5,6), it has one solution
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