Question

*Calc*
Probably making this question harder than it needs to be... question below

Answer 1

Find dx/dt when x = 3, y = 4 and dy/dt = 2

x^2 + y^2 = 25

Answer 2

Derivative: 2x + 2y\(\dfrac{dy}{dt}\) = 0

Do I just need to substitute the values in now or is there something more?

Answer 3

it should be like this :-
\[\large \bf 2x \frac{dx}{dt}+2y \frac{dy}{dt}=0\]
plug x = 3, y = 4 and dy/dt = 2 into it and solve for dx/dt

Answer 4

\(2(3)\dfrac{dx}{dt} + 2(4)(2) = 0\)

\(6\dfrac{dx}{dt} + 16 = 0 \\ \dfrac{dx}{dt} = 6/16\)

Answer 5

Wait, -16/6

Answer 6

*-8/3
xD

Answer 7

haha, thanks :)

Answer 8

anytime :)

Answer 9

Can you help on some related rates problems?

Answer 10

i'll try