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Mathematics 13 Online
OpenStudy (sleepyjess):

@mayankdevnani

OpenStudy (sleepyjess):

If the radius of a sphere is increasing at 1 cm/s, find the rate of change of its volume when the radius is 6 cm. Going to try this one first and see if I get it

OpenStudy (sleepyjess):

V = 4/3 \(\pi r^3\) dV/dt = 4/3 \(\pi (3r^2)\)dr/dt dV/dt = 4 \(\pi r^2\)dr/dt r = 6 dr/dt = 1cm/s dV/dt = 4*\(\pi\)*36*1cm/s dV/dt = 144\(\pi\)cm^3/s?

OpenStudy (queenbb):

plz help my question

OpenStudy (sleepyjess):

Did I do it right?

TheSmartOne (thesmartone):

That's correct :)

OpenStudy (sleepyjess):

Yay! :)

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