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Mathematics 17 Online
OpenStudy (princesskitty01):

Will medal and fan for anyone one who helps me

OpenStudy (princesskitty01):

The temperature of a chemical reaction ranges between 20 degrees Celsius and 160 degrees Celsius. The temperature is at its lowest point when t = 0, and the reaction completes 1 cycle during an 8-hour period. What is a cosine function that models this reaction? f(t) = −90 cos (pi over 4t) + 70 f(t) = −70 cos (pi over 4t) + 90 f(t) = 70 cos (8t) + 90 f(t) = 90 cos (8t) + 70

OpenStudy (princesskitty01):

i think B sorry was doing the others

OpenStudy (campbell_st):

well start by looking at the period of the curve you know the period is 8 hours and in a cos function \[y = acos(bx) \] the period is \[period = \frac{2\pi}{b}\] so then using the given information \[8 = \frac{2\pi}{b}\] solve for b... when you find b you will eliminate 2 answer choices then work on the amplitude and phase shift

OpenStudy (princesskitty01):

okay

OpenStudy (campbell_st):

next find the amplitude of the curve if it has a minimum of 20 and max of 160 the coss curve is centered between those values... so to find centre add the 2 limit values and divide by 2, that will give the value of a in \[y = acos(bx)\]

OpenStudy (princesskitty01):

okay

OpenStudy (campbell_st):

can you check your 1st 2 answer choices are they -90 and -70 or should they be 90 and 70..?

OpenStudy (princesskitty01):

thx

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