Will medal and fan for anyone one who helps me
The temperature of a chemical reaction ranges between 20 degrees Celsius and 160 degrees Celsius. The temperature is at its lowest point when t = 0, and the reaction completes 1 cycle during an 8-hour period. What is a cosine function that models this reaction? f(t) = −90 cos (pi over 4t) + 70 f(t) = −70 cos (pi over 4t) + 90 f(t) = 70 cos (8t) + 90 f(t) = 90 cos (8t) + 70
i think B sorry was doing the others
well start by looking at the period of the curve you know the period is 8 hours and in a cos function \[y = acos(bx) \] the period is \[period = \frac{2\pi}{b}\] so then using the given information \[8 = \frac{2\pi}{b}\] solve for b... when you find b you will eliminate 2 answer choices then work on the amplitude and phase shift
okay
next find the amplitude of the curve if it has a minimum of 20 and max of 160 the coss curve is centered between those values... so to find centre add the 2 limit values and divide by 2, that will give the value of a in \[y = acos(bx)\]
okay
can you check your 1st 2 answer choices are they -90 and -70 or should they be 90 and 70..?
thx
Join our real-time social learning platform and learn together with your friends!