Question

5+5i/6+5i

Answer 1

as in "divide and write in standard form?

Answer 2

yes

Answer 3

I know you multiply the conjugate of the equation in the denominator

Answer 4

multply top and bottom by the conjugate of the denominator
the conjugate of \(a+bi\) is \(a-bi\) and this works because \[(a+bi)(a-bi)=a^2+b^2\] a real number

Answer 5

\[\frac{5+5i}{6+5i}\times \frac{6-5i}{6-5i}\] is step one

Answer 6

the denominator is a no braniner, \[6^2+5^2=36+25=61\] all the work is in the top

Answer 7

43+5i/61 ?

Answer 8

I mean 43+15i/61

Answer 9

numerator is wrong

Answer 10

oh i see what i did wrong

Answer 11

okay

Answer 12

55+5i/61?

Answer 13

yes

Answer 14

and don't forget two write it in standard form when you are done

Answer 15

try to put brackets where they should go, (55+5i)/61

Answer 16

It should be in standard form so
\[\frac{ 55 }{ 61 }+\frac{ 5i }{ 61 }\]

Answer 17

thank you