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Ok if something says d/dx than integral (x^2+4)^5 is the answer just what is already shown?
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Yes, \[\Large \frac{d}{dx}\int(x^2+4)^5dx = (x^2+4)^5\] since, \[\Large \frac{d}{dx}\int f \ '(x)dx = f(x)\]
Thank you @jim_thompson5910 :)
no problem
@jim_thompson5910 it wouldn't matter if the d/dx was inside the integral right?
if it's inside the integral, then you'll have \[\Large \int \frac{d}{dx}\left(f(x)\right)dx = f(x)+C\] where C is a constant
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Oh so your just adding a c? so it would be (x^2+4)^5+c
yes, usually it's capital C
oh ok
\[\Large \int f \ '(x)dx = f(x)+C\]
\[\Large \frac{d}{dx}\Big[f(x)\Big] = f \ '(x)\]
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ok, yes that makes sense
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